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3 years ago

a circular swimming pool is 22 feet across. how many square feet of material cover the bottom of the pool?

2 answers:

7 0

The formula for the area of a circle is A=(pi)r^2. The diameter of a circle is how far across it is, and r is the radius and exactly half of the diameter. The radius is 11 feet. All you have to do at that point is plug the numbers into the equation. You will need 380.13 square feet of material to cover the bottom of the pool.

Mama L [17]3 years ago

5 0

Area of a circle is pr^2, or when using d as r=d/2 is (pd^2)/4. It says that the pool is 22 feet across so that means the diameter of the pool is 22 ft so

A=(p*22^2)/4

A=484p/4

A=121p ft^2

A≈380.13 ft^2

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cupoosta [38]

$\bf \begin{cases}
(n^4)^p=n^{12}\to &n^{4\cdot p}=n^{12}\to 4p=12
\\
&\qquad \uparrow \\
&\textit{same bases, thus}\\
&\qquad \downarrow 
\\
n^3\cdot n^q=n^6\to &n^{3+q}=n^6\to 3+q=6
\end{cases}
\\\\\\
thus\implies 
\begin{cases}
4p=12\implies p=\frac{12}{4}
\\\\
3+q=6\implies q=6-3
\end{cases}
\\\\

\\\\
then\implies p\cdot q=\boxed{?}$

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3 years ago

A pendulum is 45 cm long. When it swings, it travels along the arc of a circle and covers a distance of 27.5 cm. Calculate the a

11Alexandr11 [23.1K]

Answer: The angle through which the pendulum travels = $35^{\circ}$ .

Step-by-step explanation:

Formula: Length of arc: $l= r\theta$ , where r= radius ( in radians) , $\theta$ = central angle.

Given: Length of pendulum (radius) = 45 cm

Length of arc= 27.5 cm

Put these values in the formula, we get

$27.5=45\theta\\\\\Rightarrow\theta=\dfrac{27.5}{45}=\dfrac{275}{450}\\\\\Rightarrow\ \theta=\dfrac{11}{18}\text{ radians}$

In degrees ,

$\theta=\dfrac{11}{18}\times\dfrac{180}{\pi}=\dfrac{110\times7}{22} \ \ \ \ [\pi=\dfrac{22}{7}]$

$\theta=35^{\circ}$

Hence, the angle through which the pendulum travels = $35^{\circ}$ .

4 0

3 years ago

What is the solution to the equation 3 over 1⁄2 plus P. equals 5 over 1⁄4

Firdavs [7]

Answer:

C hdgkddjgxjvvnCbbcBcgsjgzjvzjvhfhfh

8 0

3 years ago

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

We expect your answer is supposed to be Step 4.

7 0

4 years ago

(p2+3p+6)+(2p2+6p+6) Please get this right. AND DON'T SPAM!

gayaneshka [121]

(p² + 3p + 6) + (2p² + 6p + 6)

First you must combine (aka sum) like terms. Like terms are numbers that have matching variables OR are numbers with out variables OR have matching variables with matching exponents. In this case the like terms are p² and 2p² (they both have the exponent p that is squared); 3p and 6p (they both have the variable p attached); and 6 and 6 (both numbers without variables)

(p² + 2p²) + (3p + 6p) + (6 + 6)

3p² + 9p + 12

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

3 years ago