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rusak2 [61]
3 years ago
8

Find the integral of 1/sqrt(x^2-9)

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
Let x = 3secβ, then dx = 3secβtanβ

∫dx/√(x²-9) = ∫[(3secβtanβ)/(3tanβ)]dβ
                 = ∫secβdβ
                 = ln |tanβ - secβ| + c
                 = ln |√(x² - 9)/3 - x/3| + C
                 = ln |√(x² - 9)/x| + C
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Really need help on #15 please.
ollegr [7]

Step-by-step explanation:

Let's call L the length and W the width.  The length is 10 feet longer than the width, so:

L = W + 10

The area is the length times width, so:

119 = LW

Substituting:

119 = (W + 10) W

119 = W² + 10W

0 = W² + 10W − 119

0 = (W + 17) (W − 7)

W = -17 or 7

Since W must be positive, W = 7.

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The length and width are 17 feet and 7 feet, respectively.

5 0
3 years ago
How many roots does a quadratic have if the discriminant if prime?
scZoUnD [109]

"The discriminant is prime?" I haven't heard that one before.

Here are the general rules:

1. a positive discriminant results in two real, unequal roots.

2. a zero discr. results in two real, equal roots.

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5 0
2 years ago
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leonid [27]
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3 0
2 years ago
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GuDViN [60]

Answer:

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7 0
3 years ago
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