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Lorico [155]
3 years ago
8

Solve −2(n+3)−4=8 . The solution is n= .

Mathematics
1 answer:
Anton [14]3 years ago
3 0

Answer:

n= -9

Step-by-step explanation:

Simplifying

-2(n + 3) + -4 = 8

Reorder the terms:

-2(3 + n) + -4 = 8

(3 * -2 + n * -2) + -4 = 8

(-6 + -2n) + -4 = 8

Reorder the terms:

-6 + -4 + -2n = 8

Combine like terms: -6 + -4 = -10

-10 + -2n = 8

Solving

-10 + -2n = 8

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + -2n = 8 + 10

Combine like terms: -10 + 10 = 0

0 + -2n = 8 + 10

-2n = 8 + 10

Combine like terms: 8 + 10 = 18

-2n = 18

Divide each side by '-2'.

n = -9

Simplifying

n = -9

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The diagram shows a 5 cm x 5 cm x 5 cm cube.
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Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

\sqrt{a^2+b^2}

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths a_1, a_2, a_3, \ldots, a_n is

\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}

So the solution here is

\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm

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Step-by-step explanation:


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