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sergejj [24]
4 years ago
15

Question 5 Work out 524 + 344 =

Mathematics
2 answers:
JulsSmile [24]4 years ago
7 0
524 + 344 = 868
5+3=8
2+4=6
4+4=8
Which makes 868 all together
Rainbow [258]4 years ago
3 0

Answer:

868

Step-by-step explanation:

5 2 4

+ 3 4 4

------------

4 + 4 = 8

5 2 4

+ 3 4 4

------------

         8

2 + 4 = 6

5 2 4

+ 3 4 4

------------

    6   8

5 + 3 = 8

5 2 4

+ 3 4 4

------------

 8   6   8

524 + 344 = 868

Hope this helps.

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3 years ago
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What does a variable allow you to do that you couldn't do before
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For example x^2=25
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3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared
navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

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Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

#SPJ1

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If line KN is a median of triangle KLM, find KL.
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The answer is KL= 11 because x =4
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