Question

Write the equation of the line, given the y and x-intercepts. a x-intercept = –68, y-intercept = –34

Answer 1

Answer:

$y=-\frac{x}{2}-34$

Step-by-step explanation:

Hello there, I can help with this one

Step 1

define two points

x-intercept=-68,this means that  when the line intercepts x (is when the value of y = 0)it  is in the point (-68,0)

Hence, we have a point

let

P1(-68,0)

y-intercept=-34,this means that  when the line intercepts y (this happens  when the value of x = 0)it  is in the point (0,-34)

P2(0,-34)

Step two

find the slope using

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$P1(x_{1},y_{1})= (-68,0)\\P2(x_{2},y_{2})= (0,-34)\\\\m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\m=\frac{-34-0}{0-(-68)}\\m=\frac{-34}{68}\\ m=-\frac{1}{2}$

Step three

find the equation of the line using

$y-y_{1}=m(x-x_{1})\\ where\\(x_{1},y_{1})\ is\ a\ known\ point$

put the values of P1 and m

P1(-68,0),m=-1/2

$y-0=-\frac{1}{2} (x-(-68))\\y=-\frac{x}{2}-\frac{68}{2}\\y=-\frac{x}{2}-34$

I hope it helps, have a nice day