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3 years ago

Find the equation of the circle with center at

1 answer:

4 0

Radius (R) is equal to the distance between the points (-2,1) and <span>(3,1)
R</span>² = (-2 - 3)² + (1 - 1)² = (-5)² + 0 = 25
R = 5

<span>Equation of the circle:
</span>(х-(-2))² + (у-1)² = 5²
(х+2)² + (у-1)² = 25

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<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

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and subtracting this from $S_n$ gives

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Now, we're given

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$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

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$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

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2 years ago

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