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satela [25.4K]
3 years ago
6

WILL GIVE BRAINLIEST: If the graph of 2x+3y − 6=0 is perpendicular to the graph of ax − 3y=5. What is the value of a?

Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer:

a = \frac{9}{2}

Step-by-step explanation:

To find the value of a, find the Slope of both the equations.

For lines to be perpendicular to each other    m_{1}m_{2}  = - 1

For line 1:

2x + 3y − 6 = 0 represent the line in y=mx +c form

3y = -2x + 6

y = \frac{-2}{3} x + \frac{6}{3}

y = \frac{-2}{3} x + 2

m_{1} = \frac{-2}{3}

For line 2:

ax - 3y = 5

ax = 5 + 3y

ax - 5 = 3y

y = \frac{ax}{3} - \frac{5}{3}

m_{2} = \frac{a}{3}

Apply the condition of perpendicularity:

\frac{-2}{3} * \frac{a}{3} = - 1

\frac{2a}{9} = 1

a = \frac{9}{2}

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