All categories

2 years ago

What is the answer to 54 & 55?

Mathematics

1 answer:

MrRissso [65]2 years ago

5 0

$\frac{d}{dx} [x^{a}] = ax^{a-1}
\\ \frac{d}{dx} [x^{-4}] = -4x^{-5}
\\ \frac{d}{dx} [x^{1/5}] = 1/5 \cdot x^{-4/5}$

You might be interested in

What is the area of this parrelogram

Dmitrij [34]

Answer:

no parallelogram, mr clean thus cannot answer.

7 0

2 years ago

How many solutions exist for the given equation?

bogdanovich [222]

Answer: Infinitely many solutions when we graph this it comes out as one straight line also try using Desmos it helps with equations like this by graphing them for you! -Your friend, Bill Cipher

Step-by-step explanation: Have a great Valentines day <3

4 0

2 years ago

Is -2 a solution to 4x^(3)-x^(2)+16x-4

sergiy2304 [10]

Answer:

Not a solution

Step-by-step explanation:

In order for $x=-2$ to be a solution, the result after substituting must be 0:

$4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0$

$4(-8)-4-32-4\stackrel{?}{=}0$

$-32-40\stackrel{?}{=}0$

$-72\neq0$

Therefore, $x=-2$ is not a solution to $4x^3-x^2+16x-4$

3 0

2 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

$\text{Minimum value }= 53$

$Q_1=62$

$Median=80$

$Q_3=86$

$\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

For second box plot

$\text{Minimum value }= 56$

$Q_1=62$

$Median=74$

$Q_3=89$

$\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value. It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range. It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0

3 years ago

Hi! What is y = x^2 -4x +5 vertex form? Please explain how you got this answer. Thanks! :)

Anarel [89]

${x}^{2} - 4x + 5 = 0 \\ {x}^{2} - 4x = - 5 \\ \\ { (\frac{b}{2} )}^{2} = ( \frac{ - 4}{2} ) = ( { - 2})^{2} = 4 \\ {x}^{2} - 4x + 4 = - 5 + 4 \\ {(x - 2)}^{2} = - 1 \\ {(x - 2)}^{2} + 1$
The last line is in vertex form, and can see the vertex is located at (2,1).

8 0

2 years ago

Read 2 more answers