Answer:
2 and 4
Step-by-step explanation:
Got it Correct on Edg:
The quadratic function y = –2(x + 4)2 – 3 with no real zeros is graphed.
Determine the values of h and k that will change the function to one with two real zeros and a vertex of (3, 2). What are the zeros of the new function?
✔ 2 and ✔ 4
Sorry for the late answer ^_^
Answer:
The standard form of the equation is 2x + 5y = -1
Step-by-step explanation:
To find this equation in standard form, we first need to find the slope of the line. We can do that by using the slope formula with the two points.
m(slope) = (y2 - y1)/(x2 - x1)
m = (1 - -3)/(-3 - 7)
m = 4/-10
m = -2/5
Now that we have the slope, we can use that along with the point in point-slope form
y - y1 = m(x - x1)
y - 1 = -2/5(x + 3)
Now that we have that, we can solve for the constant and rationalize the denominators.
y - 1 = -2/5x - 6/5
2/5x + y - 1 = -6/5
2/5x + y = -1/5
2x + 5y = -1
Answer:
Step-by-step explanation:
Given that,
The radius of a circle, r = 5 m
The central angle is 180 degrees
We need to find the area of a sector of a circle.
The formula for the area of sector of a circle is given by :
So, the area of the sector of a circle is 
.
Answer:
-3.7, -1.9, 1/2, 1/3, 1/3, 1, 1.6, 2
Step-by-step explanation:
