If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.
1 answer:
Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s
(b) 54.14 m/s
Step-by-step explanation:
The average speed over the given time interval [a,b]: = 
Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by 
(a)
(i) average speed = 

m/s
(ii) average speed = 

m/s
(iii) average speed = 

m/s
(iv) average speed = 

m/s
(v) average speed = 

m/s
(b) 

m/s
You might be interested in
C) x = -19/10 because when solving it with substitution u get x=-19/10 & y=153/10
Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Answer:
628
Step-by-step explanation:
216+412 = 628
First you get rid of the brackets by solving what's in them. Then you just add up the numbers and BOOM. The equation is solved. :-)
you take 2pi and divide it by bits stolen from the equation its explained more in the screennshot
D 35.31 is the correct answer