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3 years ago

Write 7.65040 x10-4 power in scientific notation

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

5 0

It's already in scientific notation form;

Answer of your question,

3x+46 = 10x-80

7x = 34

x = 4.85

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F(x)=3x^3-4x^2+6x and g(x)=5x^3+2x^2-3x what is f(x)-g(x)

mrs_skeptik [129]

F(x) - g(x) = -2x^3 - 6x^2 + 9x

7 0

3 years ago

Read 2 more answers

1/2−3(1/2+1)^2<br><br><br> Enter your answer, as a simplified fraction

o-na [289]

Answer:

$- \frac{25}{4}$

Step-by-step explanation:

$\frac{1}{2} -3 (\frac{1}{2} + 1)$ ²

Calculate sum

$\frac{1}{2} -3x (\frac{3}{2})$ ²

To raise a fraction to a power raise numerator and denominator to that power

$\frac{1}{2}$ -3 x $\frac{9}{4}$

Calculate product

$\frac{1}{2}$ - $\frac{27}{4}$

Subtract fractions

- $\frac{25}{4}$

4 0

3 years ago

A circular rug has a radius of 4 feet. Which of the following is the closest to the number of square inches the rug covers?

Mashcka [7]

Answer:

B. 50.24

Step-by-step explanation:

to find the area of a circle you need to use the formula

a=r²π

since the radius is 4 we put that into the equation, lets use 3.14 for pi

a=(4)²×3.14

always do exponents first

a=16×3.14

a=50.24

8 0

3 years ago

Your team gets an ice sculpture in the shape of a basketball. It has a radius of 12

cluponka [151]

Answer:

7234.56 inches cubed

Step-by-step explanation:

V=4/3 times pi times r cubed

4/3 times 3.14 times 1728

6 0

3 years ago

Q3. Consider two identical pack of cards A and B. When one card from A is taken and shuffled with the card B, the first top card

vivado [14]

Answer:

0.02

Step-by-step explanation:

Pack A and B both consisted of 52 cards. When shuffled, 51 cards in A and 53 cards in deck B. It appears that the Top card of A left with only 51 possible cards to be taken from A (since we know the Queen hadn't moved).

The two possible cases are: probability of not taking King of Hearts (from A to B), and the other were we did.

Let K= the event of taking the King of Hearts from A to B and be $B_{K}$ the occasion being the top card of B.

$P(B_{K} )=P(K)P(B_{K} |K)+P(K^{C} )P(B_{K} |K^{C} )\\$

$=\frac{1}{51} \frac{2}{53} +\frac{50}{51} \frac{1}{53}$

$=\frac{52}{2703} \\=0.02$

8 0

3 years ago