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DanielleElmas [232]
3 years ago
10

Algebra 1 please help with 6,7

Mathematics
2 answers:
AysviL [449]3 years ago
4 0

Answer:7 is I _9and 3

Step-by-step explanation:

Lorico [155]3 years ago
4 0

Your option I will be the correct answer because you don’t have to be worried about negative sign in front of x^2 because that negative sign is the reflection over the x axis and then you simply factor it out to find your root/zeros values. Root/zeros values mean x values on the graph. Hope that helps.

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Please help me with this one :(​
dimulka [17.4K]

Answer:

I can assure you, that this is not that hard. but. I will help you with one of them.

Step-by-step explanation:

audience-look it up in the dictionary

it's basically a crowd of people.

sebtence- I listened to the audio of the audio book.

4 0
3 years ago
What are the solutions to the system of equations?
svet-max [94.6K]

Answer:the third option is correct

Step-by-step explanation:

The system of equations are

y = 2x^2 - 5x - 7 - - - - - - - - - - -1

y = 2x + 2 - - - - - - - - - - - - - 2

We would equate equation 1 and equation 2. It becomes

2x^2 - 5x - 7 = 2x + 2

2x^2 - 5x - 2x - 7 - 2 = 0

2x^2 - 7x - 9 = 0

We would find two numbers such that their sum or difference is -7x and their product is - 18x^2. The two numbers are 2x and - 9x. Therefore

2x^2 + 2x - 9x - 9 = 0

2x(x + 1) - 9(x + 1) = 0

2x - 9 = 0 or x + 1 = 0

2x = 9 or x = - 1

x = 9/2 = 4.5

Substituting x = 4.5 or x = -1 into equation 2, it becomes

y = 2 × 4.5 + 2 or y = 2 × - 1 + 2

y = 11 or y = 0

Therefore, the solutions are

(4.5, 11) (- 1, 0)

6 0
3 years ago
Q2: Explain the difference between the solution to an equation and the solution to an inequality. (dba 3
CaHeK987 [17]
The solution(s) of a system of linear equations give points of intersection of specific lines or planes.

The solution(s) of a system of linear inequalities give areas of intersection wherein any specific pair of points or lines are solutions.

PROCESS-WISE there are little differences between solving systems. However, multiplication and division by negatives reverses the signs in inequalities. 
 
4 0
3 years ago
360km is 24% of what km
lawyer [7]
Let required  distance be x km
24x
----        =   360
100

x    = (100*360) / 24 =  1500 km  Answer
7 0
4 years ago
If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
4 years ago
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