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2 years ago

Need help on number 4 PLEASE HELP FAST WILL GIVE BRAINLIEST AND LOTS OF POINTS

Mathematics

1 answer:

MArishka [77]2 years ago

8 0

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What is the coefficient of x2 in this trinomial?

Scorpion4ik [409]

Answer:1

Step-by-step explanation:

(x+2)(x+3)

x^2+3x+2x+6

x^2+5x+6

Therefore the coefficient of x^2 is 1

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3 years ago

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Are the these expressions equivalent 6a + 12 and 3(3a + 4)

kow [346]

Answer:

Step-by-step explanation:

6a + 12 =? 3(3a + 4)

Distribute

6a+12 =? 3*3a + 3*4

6a+12 =? 9a +12

The expressions are not equivalent

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3 years ago

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The Comparing the Shape, Center, and Spread of Data Sets and more

MatroZZZ [7]

Answer:

Step-by-step explanation:

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3 years ago

Find the length of the hypotenuse

Darina [25.2K]

Answer:

The Hypotenuse is side just opposite to the right angle.

Step-by-step explanation:

By Pythagoras' theorem,

c^2=a^2+b^2

c^2(hypotenuse to be found)= 30^2+ 16^2

c^2=1156

Therefore, c ( i.e. the hypotenuse) will be the square root of 1156.

The square root of 1156 is 34.

<h2>Thus, c ( hypotenuse) = 34</h2>

Hope it helped :)

3 0

2 years ago

a cone with a radius of 3” has a total area of 24pie square inches. Find the volume of the cone. 12pie, 24 pie or 15 pie

Ratling [72]

Answer:

$12\pi (inches)^{2}$

Step-by-step explanation:

Given:

radius of cone = 3 inch

Total area of cone = $24\pi (inch)^{2}$

Find the volume of the cone?

We know the area of cone = $\pi r(r+s)$ -------(1)

Where r = radius

Ans s = side of the cone

Put the area value in equation 1

$24\pi=\pi r(r+s)$ -------(1)

$\frac{24\pi }{\pi r} =r+s$

$\frac{24}{ r}-r =s$

Put r value in above equation.

$s =\frac{24}{ 3}-3$

$s=8-3$

$s=5$

The side s = 5 inches

We know the side of the cone formula

$s^{2}=r^{2}+ h^{2}$

$h^{2}=s^{2}- r^{2}$

Put r and s value in above equation.

$h^{2}=5^{2}- 3^{2}$

$r^{2} = 25-9$

$r^{2} = 16$

$r = 4$

The volume of cone is

$V = \frac{1}{3} \pi r^{2} h$

Put r and h value in above equation.

$V = \frac{1}{3} \pi (3)^{2}\times 4$

$V = 12\pi (inches)^{2}$

The Volume of the cone is $12\pi (inches)^{2}$

7 0

3 years ago