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Eddi Din [679]
3 years ago
8

The graph of F(x) = x^2 is shown.

Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Given a function of a parabola (quadratic) in the form f(x) = x^2, we have a translated function as:

g(x) = a(x-b)^2

Where

  • a is the vertical compression or stretch. If a > 1, it is a vertical stretch and if 0 < a < 1, it is a vertical compression.

  • b is the horizontal translation b units to the right

The function given is p(x) = 3(x-8)^2

So it means that it is a vertical stretch with a factor 3 and the graph is shifted horizontally 8 units right

the correct answer is B

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3. What is the 9th term in the following sequence? 11, 17, 23, 29, . . . (1 point) 47 53 59 65
KatRina [158]
Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5  where T(1)=11
T(9)=6(9)+5=59
5 0
3 years ago
Is it possible to construct a triangle with side lengths of 15 inches, 17 inches, and 32 inches? Why or why not? (PLEASE HELP ME
dem82 [27]
B because the sum of 2 sides must be GREATER than the 3rd side
6 0
3 years ago
The Cubs have won
Naily [24]

First you need to figure out the games the Cubs lost. 11-7=4, so they lost 4 games.

Now you must plug in the ratio of games lost to games played. You know they lost 4 games and played 11, so the ratio would be 4:11.

I hope you find this helpful :)

4 0
3 years ago
Point D is the centroid of Triangle ABC. Find CD and CE.<br> DE = 9
sukhopar [10]

Given:

Point D is the centroid of Triangle ABC and DE = 9.

To find:

The measures of CD and CE.

Solution:

We know that, centroid is the intersection of medians and it divides each median in 2:1.

In triangle ABC, CE is a meaning and centroid D divided CE in 2:1. So,

Let the measures of CD and DE are 2x and x respectively.

DE = 9                (Given)

x=9

Now,

CD=2x

CD=2(9)

CD=18

And,

CE=CD+DE

CE=18+9

CE=27

Therefore, the measure of CD is 18 units and the measure of CE is 27 units.

6 0
3 years ago
The local oil changing business is very busy on Saturday mornings and is considering expanding. A national study of similar busi
eimsori [14]

Answer:

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=4.2 represent the sample mean  

s=1.4 represent the sample standard deviation  

n=16 represent the sample selected  

\alpha=0.05 significance level  

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is different from 3.6, the system of hypothesis would be:    

Null hypothesis:\mu = 3.6    

Alternative hypothesis:\mu \neq 3.6    

If we analyze the size for the sample is < 30 and we know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714

Critical values

On this case since we have a bilateral test we need to critical values. We need to use the t distribution with df=n-1=16-1=15 degrees of freedom. The value for \alpha=0.05 and \alpha/2=0.025 so we need to find on the t distribution with 15 degrees of freedom two values that accumulates 0.025 of the ara on each tail. We can use the following excel codes:

"=T.INV(0.025,15)" "=T.INV(1-0.025,15)"

And we got t_{crit}=\pm 2.131    

So the decision on this case would be:

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131  

Rejection Zone: t_{calculated} or t_{calculated}>2.131

Conclusion    

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

3 0
3 years ago
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