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aleksandr82 [10.1K]
3 years ago
6

You can use a system of equations to graph and solve the polynomial equation 3x3 + x= 2x2 + 1. Which statement is true?

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

The y-coordinates of the solutions to the system and the zeros of the equation are not equal

Step-by-step explanation:

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Three times a number plus 12 minus 5 times the same number is 22. What is the number?​
Ilia_Sergeevich [38]

Answer:3

Explanation: 3x5=15+12=27-5=22

5 0
3 years ago
Solve for j.<br>-2j + 39 = 111<br>j=<br>​
olga_2 [115]

Answer:

reeeeeerre

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
If you have an old fish tank in the form of a circular cylinder and it is 2 feet in diameter and 6 feet tall, how many cubic fee
yuradex [85]

Answer:

The old fish tank hold <u>18.84 cubic feet</u> of water.

Step-by-step explanation:

Given:

An old fish tank in the form of a circular cylinder and it is 2 feet in diameter and 6 feet tall.

Now, to find the cubic feet of water the fish tank hold.

Dimensions of old fish tank are:

<em>Diameter is 2 feet so. we find the radius first.</em>

Radius (r) = \frac{Diameter}{2}=\frac{2}{2}=1\ feet.

Height (h) = 6\ feet.

Now, to get the cubic feet off water the tank hold we put formula:

<u><em>(Taking the value of π as 3.14.)</em></u>

Volume=\pi r^2h\\\\Volume=3.14\times 1^2\times 6\\\\Volume=3.14\times 1\times 6\\\\Volume=18.84\ cubic feet.

Therefore, the old fish tank hold 18.84 cubic feet of water.

7 0
2 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
Adds up to 13 multiplies to -48
fiasKO [112]
You only need two numbers to do that.
The numbers are  16  and  -3 .

           16  -  3  =  13

         (16) x (-3)  =  -48
7 0
3 years ago
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