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LenaWriter [7]
3 years ago
13

Amelia used 6 liters of gasoline to drive 48 kilometers.

Mathematics
2 answers:
Setler79 [48]3 years ago
5 0

Answer:

Amelia drive 8 kilometers per liter.

It required 0.125 liters to drive 1 kilometer.

Step-by-step explanation:

Consider the provide information.

Amelia used 6 liters of gasoline to drive 48 kilometers.

This can be written as:

6 liters = 48 kilometers

Divide both the sides by 6.

6/6 liters = 48/6 kilometers

1 liters = 8 kilometers

Amelia drive 8 kilometers per liter.

Now calculate how many liters does it take to drive 1 kilometer?

6 liters = 48 kilometers

Divide both the sides by 48.

6/48 liters = 48/48 kilometers

0.125 liters = 1 kilometers

Hence, it required 0.125 liters to drive 1 kilometer.

Margarita [4]3 years ago
4 0
For every liter she used, she drove 8 kilometers. In this problem you are finding the unit rate. In order to do this you divide 48 (kilometers) by 6 (liters of gasoline).

48 Divided by 6 equals to 6 Kilometers
—- —-
6 Divided by 6 equals to 1 Liter

For the second question you divide the liter by 6. Amelia used 0.1666 liters of gasoline per kilometer. 0.1666 is equivalent to 1/6.
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The front of an A-frame cabin in a national park is the shape of a triangle with an area of 564 ft.² if the height is 1 feet les
aleksandrvk [35]

Answer:

Base = 24 ft; height = 47 ft  

Step-by-step explanation:

The formula for the area of a triangle is

A = ½bh

Let x = the base. Then

2x - 1 = the height

\begin{array}{ccc}A & = & \dfrac{1}{2}bh\\\\564 & = & \dfrac{1}{2}x(2x - 1)\\ \\1128 & = & x(2x - 1)\\& = & 2x^{2} - x\\2x^{2} - x - 1128 & = & 0\\(2x + 47)(x - 24) & = & 0\\2x + 47 = 0 &\qquad & x - 24 = 0\\2x = -47 & \qquad & x = \mathbf{24}\\x = -23.5 & \qquad & \\\end{array}

We reject the negative value, so x = 24 ft

Base = x = 24 ft

Height = 2x - 1 = 2(24)-1 = 48 - 1 = 47 ft

Check:

564 = ½ × 24 × 47

564 = 564

OK

3 0
3 years ago
PLEASE NEED THIS DONE AS FAST AS POSSIBLE!!!!!!!!!!!!!!!!!<br> IT MUST BE CORRECT
LuckyWell [14K]

Answer:

1)7.288 feet

2)11.6 feet

3)safe

4) 3.7 feet

5) ∅= tan^{-1}(1.5) = 56.31 degrees

6)∅1= tan^{-1}(2) = 63.43 degrees

  ∅2= tan^{-1}(1.2) = 50.19 degrees

Step-by-step explanation:

1) The door barn is rectangular in shape. The length is 9 feet and The angle between diagonal and side is 39 degrees.

Applying trigonometry,

tan(39) = \frac{opposite}{adjacent} = \frac{s}{9} = 0.809

Thus, s= (9)(0.809) = 7.288 feet

2) Applying pythagoras theorm,

   (Diagonal)^{2} = (9)^{2} + (7.288)^{2} =134.115

  Diagonal length (d) = 11.58 feet. Nearest tenth place = 11.6 feet

3) The length of ladder is 14 foot and height from ground is 13.5 feet.

Applying trigonometry,

sin(∅) =  \frac{opposite}{hypotenous} = \frac{13.5}{14} = 0.964

∅ = angle of elevation = sin^{-1}(0.964) = 74.57 ≈ 75 degrees.

Thus tractor can climb safely.

4)Applying, pythgoras theorm,

14^{2} = (13.5)^{2}  + x^{2}

x = \sqrt{14^{2}-(13.5)^{2}} = 3.708

Thus, ladder should be placed at distance 3.7 feet

5)Let angle of elevation be ∅.

  tan(∅) = \frac{30}{20} = 1.5

  ∅= tan^{-1}(1.5) = 56.31 degrees

6)After moving 5 feet closer to barn, Let angle of elevation for light near barn be ∅1 and for farther one be ∅2.

Thus,

tan(∅1) = \frac{30}{15} = 2

  ∅1= tan^{-1}(2) = 63.43 degrees

tan(∅2) = \frac{30}{25} = 1.2

  ∅2= tan^{-1}(1.2) = 50.19 degrees

3 0
3 years ago
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