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LenaWriter [7]
2 years ago
13

Amelia used 6 liters of gasoline to drive 48 kilometers.

Mathematics
2 answers:
Setler79 [48]2 years ago
5 0

Answer:

Amelia drive 8 kilometers per liter.

It required 0.125 liters to drive 1 kilometer.

Step-by-step explanation:

Consider the provide information.

Amelia used 6 liters of gasoline to drive 48 kilometers.

This can be written as:

6 liters = 48 kilometers

Divide both the sides by 6.

6/6 liters = 48/6 kilometers

1 liters = 8 kilometers

Amelia drive 8 kilometers per liter.

Now calculate how many liters does it take to drive 1 kilometer?

6 liters = 48 kilometers

Divide both the sides by 48.

6/48 liters = 48/48 kilometers

0.125 liters = 1 kilometers

Hence, it required 0.125 liters to drive 1 kilometer.

Margarita [4]2 years ago
4 0
For every liter she used, she drove 8 kilometers. In this problem you are finding the unit rate. In order to do this you divide 48 (kilometers) by 6 (liters of gasoline).

48 Divided by 6 equals to 6 Kilometers
—- —-
6 Divided by 6 equals to 1 Liter

For the second question you divide the liter by 6. Amelia used 0.1666 liters of gasoline per kilometer. 0.1666 is equivalent to 1/6.
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First, simplify 2x + 4y - 5 + 3x + 8 - 4y as follows:

Add like terms

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Add like terms together

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Therefore, x + x + y + y + y + y - 5 + x + x + x + 8 - 4y is equivalent to 2x + 4y - 5 + 3x + 8 - 4y

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<u><em>Second Option:</em></u>

<u><em /></u>6xy + 3 - 4y<em> (cannot be simplified further)</em>

<em />6xy + 3 - 4y\neq 2x + 4y - 5 + 3x + 8 - 4y<em />

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<em />-8y + 5x - 3 \neq  2x + 4y -5 + 3x + 8 - 4y<em />

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<u><em>Fourth Option:</em></u>

<u><em /></u>5x + 3<u><em /></u>

<u><em /></u>5x + 3 = 2x + 4y - 5 + 3x + 8 - 4y<u><em /></u>

Therefore:

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