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3 years ago

What is the value of x? x+4\5 =11

Mathematics

2 answers:

ivanzaharov [21]3 years ago

8 0

Answer: 10 1/5, i took the test and this was the right answer

solong [7]3 years ago

3 0

It is x + (4/5) = 11

It is this because of PEMDAS, if you learned that.

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1.) Simplify the expression.

miss Akunina [59]

Answer:

$sin ( u +\frac{\pi}{2} ) = cos (u)$

Step-by-step explanation:

Let us use the identity

sin(A+B)= cos(A) sin(B)+cos (B) sin(A) to simplify the given expression

Then

$sin(u + \frac{\pi}{2})= \cos \left(u\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(u\right)$ --------------------(1)

Here

$cos (\frac{\pi}{2}) = 0\\$ ---------------------(2)

$sin(\frac{\pi}{2})= 1$ ---------------------(3)

Substituting the values in (1)

$sin(u + \frac{\pi}{2})= \cos \left(u\right)(1)+(0)\sin \left(u\right)$

$sin(u + \frac{\pi}{2})= \cos \left(u\right) + 0$

$sin(u + \frac{\pi}{2})= \cos \left(u\right)$

4 0

3 years ago

How many purple marbles are there?

Ksenya-84 [330]

If Yellow is x
Then purple is 3x-8
The total is 64, so x+3x-8=64
x=18
3*18-8=46

8 0

3 years ago

X²+4x+20=0

andrezito [222]

Step-by-step explanation:

The general form of the quadratic equation is :

$ax^2+bx+c$

The given equation is x²+4x+20=0

On comparing the given equation and the general equation, we find that

a = 1, b = 4 and c = 20

Hence, the correct option is a=1 b =4 c = 20.

If the equation is 2x²+6x+5=0, then

a = 2, b = 6 and c = 5

If the equation is -2x²+x+5

a = -2, b = 1 and c = 5

7 0

3 years ago

What is the missing side length in the triangle?

pogonyaev

Answer:

Step-by-step explanation:

Find the last side of the triangle using the Pythagorean theorem.

$a^{2} +b^{2} =c^{2} \\a^{2} +28^{2}=53^{2} \\a^{2} = 53^{2} -28^{2}\\a=45$

4 0

3 years ago

A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af

fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = $T+(T_0-T)e^{-kt}$

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

$T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110$

So equation is

$T(t) = 40+(30)e^{-0.8110t}\\$

When t=1,

we get

$T(1) = 40+(30)e^{-0.8110}\\\\=53.3324$

5 0

3 years ago