Your distance from Seattle after two hours of driving at 62 mph, from a starting point 38 miles east of Seattle, will be (38 + [62 mph][2 hr] ) miles, or 162 miles (east).
Your friend will be (20 + [65 mph][2 hrs] ) miles, or 150 miles south of Seattle.
Comparing 162 miles and 150 miles, we see that you will be further from Seattle than your friend after 2 hours.
After how many hours will you and your friend be the same distance from Seattle? Equate 20 + [65 mph]t to 38 + [62 mph]t and solve the resulting equation for time, t:
20 + [65 mph]t = 38 + [62 mph]t
Subtract [62 mph]t from both sides of this equation, obtaining:
20 + [3 mph]t = 38. Then [3 mph]t = 18, and t = 6 hours.
You and your friend will be the same distance from Seattle (but in different directions) after 6 hours.
Answer:
a) ![v = \frac{[L]}{[T]} = LT^{-1}](https://tex.z-dn.net/?f=%20v%20%3D%20%5Cfrac%7B%5BL%5D%7D%7B%5BT%5D%7D%20%3D%20LT%5E%7B-1%7D)
b) ![a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}](https://tex.z-dn.net/?f=%20a%20%3D%20%5Cfrac%7B%5BL%7D%7BT%7D%5E%7B-1%7D%5D%7D%7B%7BT%7D%7D%3D%20L%20T%5E%7B-1%7D%20T%5E%7B-1%7D%3D%20L%20T%5E%7B-2%7D)
c) ![\int v dt = s(t) = [L]=L](https://tex.z-dn.net/?f=%20%5Cint%20v%20dt%20%3D%20s%28t%29%20%3D%20%5BL%5D%3DL)
d) ![\int a dt = v(t) = [L][T]^{-1}=LT^{-1}](https://tex.z-dn.net/?f=%20%5Cint%20a%20dt%20%3D%20v%28t%29%20%3D%20%5BL%5D%5BT%5D%5E%7B-1%7D%3DLT%5E%7B-1%7D)
e) ![\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bda%7D%7Bdt%7D%3D%20%5Cfrac%7B%5BL%5D%5BT%5D%5E%7B-2%7D%7D%7BT%7D%20%3D%20%5BL%5D%5BT%5D%5E%7B-2%7D%20%5BT%5D%5E%7B-1%7D%20%3D%20LT%5E%7B-3%7D)
Step-by-step explanation:
Let define some notation:
[L]= represent longitude , [T] =represent time
And we have defined:
s(t) a position function
Part a
If we do the dimensional analysis for v we got:
Part b
For the acceleration we can use the result obtained from part a and we got:
Part c
From definition if we do the integral of the velocity respect to t we got the position:
And the dimensional analysis for the position is:
Part d
The integral for the acceleration respect to the time is the velocity:
And the dimensional analysis for the position is:
Part e
If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:
The number -3 written as a logarithm with a base of 2 is log₂(0.125) or log₂(1/8)
<h3>What are logarithms?</h3>
As a general rule, logarithms are mathematical expressions that are written in the form log(x) or ln(x), for natural logarithms
<h3>How to rewrite the number as a logarithm?</h3>
The number is given as:
x = -3
The base of the logarithm is given as:
Base = 2
To rewrite the given number as a base of 2, we take the exponent of the number where the base is 2
This is represented as:
Number =2^-3
Apply the power rule of indices
Number =1/2^3
Evaluate the exponent
Number = 1/8
Evaluate the quotient
Number = 0.125
Hence, when the number -3 is rewritten as a logarithm with base 2, the equivalent logarithm expression is log₂(0.125) or log₂(1/8)
Read more about logarithm at:
brainly.com/question/20785664
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