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quester [9]
3 years ago
12

Mei spent $25 on a magazine and some candy bars. If the magazine cost $5 and each candy bar cost $4, then how many candy bars di

d she buy?
Mathematics
2 answers:
Triss [41]3 years ago
7 0
5 because 5+4x5=25 therefore she bought 5 candy bars
lara31 [8.8K]3 years ago
3 0
5 Candy bars!

We know that this is our equation: $5 + $4x = $25 <= We have to find the value of x 

$5 + $4x = $25
-5                 -5

$4x = $20
  -         -
 4         4

x = $5 

Hope this helped!
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Would you rather have 1/3 of a cake or 0.3? Use mathematical reasoning to justify your choice?
Vinil7 [7]

1/3 because if you cut a cake into 3 parts you will have a lot more but 0.3 of a cake is not a lot.

4 0
3 years ago
Read 2 more answers
Trevon is making payments on a car that costs $26,555. He makes 36 equal payments.If he rounds the equal payments up to the near
scoundrel [369]

Trevon will overpay around $13

Further explanation:

One time payment will be calculated by dividing the total amount by 36 and then the answer will be rounded off to nearest dollar

So,

Given

Cost\ of\ car=\ 26555\\Number\ of\ payments=36\\Amount\ of\ one\ payment = \frac{26555}{36}\\=737.64

One time payment is 737.64. Rounding off to nearest dollar gives us 738.

If 738 is paid 36 times,

Total\ amount\ paid=36*738=26568

The amount that will be overpaid is:

=26568-26555=13

Trevon will overpay around $13

Keywords: Installments, Profit

Learn more about installments at:

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6 0
3 years ago
Can some please help me with Algebra 2 work? Its problems 45-48 all and 53-57 just odd numbers
Elanso [62]

45)

E = mc²     <em> (solve for "m" by dividing both sides by c²)</em>

E/c² = m

46)

c(a + b) - d = f  <em>(to solve for "a"; add "d", divide by "c" and then subtract "b")</em>

c(a + b)     = f + d

(a + b)       = (f + d)/c

a              = (f + d)/c  - b

47)

z = πq³h  <em> (solve for "h" by dividing both sides by πq³)</em>

z/πq³ = h

48)

(x + y)/z - a = b   <em> (solve for "y"; add "a", multiply by "z", and then subtract "x")</em>

(x + y)/z      = b + a

(x + y)         = z(b + a)

     y           = z(b + a) - x

53)

5x - 9 = 11x + 3

     -9 = 6x + 3      <em>subtracted 5x from both sides</em>

    -12 = 6x          <em>subtracted 3 from both sides</em>

      -2 = x           <em>divided both sides by 6</em>

55)

5.4(3k - 12)   +   3.2(2k + 6) = -136

16.2k - 64.8   +  6.4k + 19.2 = -136      <em>distributed 5.4 and 3.2</em>

22.6k - 45.6 = -136             <em>added like terms (16.2k + 6.4k and -64.8 + 19.2</em>

22.6k = -90.4                    <em>added 45.6 to both sides</em>

      k = -4                       <em>divided both sides by 22.6</em>

57)

(4/9)y + 5 = (-7/9)y - 8

4y + 45 = -7y - 72           <em>multiplied by 9 to clear the denominator</em>

11y + 45 = -72                 <em>added 7y to both sides</em>

11y         = -99                  <em>subtracted 45 from both sides</em>

y            = -9                    <em>divided both sides by 11</em>



8 0
4 years ago
What are t + 8 + 3t terms and like
Bond [772]

Answer:

t+8+3t

8+4t

Step-by-step explanation:

I guess the question is incomplete

3 0
3 years ago
A horse walks around a circular track while its trainer stands in the center. The trainer is 14 feet from the horse at all times
max2010maxim [7]

The horse traveled 439.6 feet after walking around the track 5 times

<u><em>Solution:</em></u>

Given that, horse walks around a circular track while its trainer stands in the center

The trainer is 14 feet from the horse at all times

Therefore, radius of circular track = 14 feet

The circumference of circle is the distance traveled by horse for 1 lap

<em><u>The circumference of circle is given as:</u></em>

C = 2 \pi r

Where, "r" is the radius and \pi is a constant equal to 3.14

C = 2 \times 3.14 \times 14\\\\C = 87.92

Thus the distance traveled by horse for one time in circular track is 87.92 feet

<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>

Multiply the circumference by 5

distance = 5 \times 87.92\\\\distance = 439.6

Thus the horse traveled 439.6 feet after walking around the track 5 times

5 0
3 years ago
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