Okay what’s the rest of the question ?
Answer:
uduysf
Step-by-step explanation:
fueasdhufhfad uafdcbxz vdvuxcz
Answer:
Step-by-step explanation:
\frac{4}{3x²-23x+40}
=\frac{4}{3x²-15x-8x+40}
=\frac{4}{3x(x-5)-8(x-5)}
=\frac{4}{(x-5)(3x-8)}
=\frac{4(x-3)}{(x-5)(3x-8)(x-3)}
2.
\frac{9x}{3x²-17x+24}
=\frac{9x}{3x²-9x-8x+24}
=\frac{9x}{3x(x-3)-8(x-3)}
=\frac{9x}{(x-3)(3x-8)}
=\frac{9x(x-5)}{(3x-8)(x-5)(x-3)}
I have attached the solutions!! Please see the photo :)
<span>y = x2 + 10x + 25? x = -10 x = -5 x = 5</span>
