Oh sorry to disappoint u i got the answer wrong lol i tried
<span>-5x+2y=9 3x+5y=7
-3x -3x
5y=-3x+7
5 5 5
y=-3/5x + 1.4
so um maybe -1,2
i suck. </span>
You'll need to use parentheses to indicate what is under the first radical sign and what is not. Did you mean radical(36a) or just radical 36?
I will assume that you meant radical(36a).
Then you have [radical(36a}*(b^4)*c^5.
This comes out to 6sqrt(a)*b^4*c^5.
Answer:
1. zeros are -2 and 1
2. zeros are -1 and 3
3. zeros are -3 and 1
4. zeros are -1
5. no zeros
6. no zeros
Step-by-step explanation:
Zeros are points on the graph that are x-intercepts; in the graph we can see that they cross -2 and 1 on the 1st equation, -1 and 3 on the 2nd equation, -3 and 1 in the 3rd equation, and -1 in the 4th equation. Since it intersects no x-intercepts in the 5th and 6th equation, it has no zeros.
1/169) / (1/3
1/169 *3
3/169
Hope this helps :)