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Ostrovityanka [42]
3 years ago
8

T F IfA and B are similar matrices, then AT=BT

Mathematics
1 answer:
muminat3 years ago
7 0

Answer:

Step-by-step explanation:

We know that for two similar matrices A and B exists an invertible matrix P for which

[tex]B = P^{-1} AP[/tex]

∴ B^{T} = (P^{-1})^{T} A^{T} P^{T} \\

Also P^{-1}P = I\\

and (P^{-1})^{T} = (P^{T})^{-1}

∴(P^{-1})^{T}P^{T} = I

so, B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}

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What equation do you get when you solve -q=a+sx for x?​
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Answer:iidff

Step-by-step explanation:

rr

8 0
3 years ago
All I need is help on these two so plz help me finish !!
aivan3 [116]

Answer:5.86 9.26

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a
yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0
3 years ago
A random sample of 85 group leaders, supervisors, and similar personnel revealed that a person spent an average 6.5 years on the
strojnjashka [21]

Answer:

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

Step-by-step explanation:

<u><em>Step( i ):-</em></u>

<em>Given random sample size 'n' =85</em>

<em>Mean of the sample size x⁻ = 6.5 years</em>

<em>Standard deviation of Population = 1.7 years</em>

<em>Level of significance = 0.95 or 0.05</em>

<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the Population is determined by</em>

<em></em>(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })<em></em>

<em></em>(6.5 - 1.96\frac{1.7}{\sqrt{85} } , 6.5 + 1.96 \frac{1.7}{\sqrt{85} })<em></em>

<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>

<em>( 6.1386 , 6.8614)</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

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3 years ago
Find all numbers whose absolute value is 3
ratelena [41]
-3 and 3, both three away from 0
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3 years ago
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