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choli [55]
3 years ago
8

Sofia is learning to knit. After her first three stitches, she had to undo the last two. Then she made three more stitches and a

gain, had to undo the last two. If this pattern continues, how many stitches will Sofia have to make before she has six good stitches?
Solve it please :(
Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0
She’ll have to make 4 more stitches in order to get 6 good ones. Each time she creates 3 she undoes 2 which after 4 more times would leave her with 6 good stitches.
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¿Cuál de las siguientes funciones es una función constante? a. Y=x+1 b. Y=x+2 c. X=y+3 d. Y=3
goldenfox [79]

Answer:

Option D y=3

Step-by-step explanation:

The question in English is

Which of the following functions is a constant function?

we know that

A <u>constant function</u> is a function whose output value is the same for every input value

so

<u><em>Verify each case</em></u>

case A) y=x+1

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case B) y=x+2

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case C) x=y+3

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case D) y=3

This is a constant function

Is a function whose output value is the same for every input value

3 0
3 years ago
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kati45 [8]
Not similar, since the ratio of corespondent side is not constant
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4 0
3 years ago
At Sanger’s auto garage, three out of every five cars brought in for service need an oil change. Of the cars that need an oil ch
Alina [70]

Answer:

The probability that a car that comes into the garage needs both an oil change and a tire rotation is \frac{12}{35}.

Step-by-step explanation:

The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:

P(B|A)=\frac{P(A\cap B)}{P(A)}

Denote the events as follows:

<em>X</em> = cars brought in for service need an oil change

<em>Y</em> = cars brought in for service need a tire rotation

The information provided is:

P(X)=\frac{3}{5}

P(Y|X)=\frac{4}{7}

Compute the value of P (X ∩ Y) as follows:

   P(Y|X)=\frac{P(X\cap Y)}{P(X)}

             \frac{4}{7}=\frac{P(X\cap Y)}{3/5}

P(X\cap Y)=\frac{4}{7}\times \frac{3}{5}

                =\frac{12}{35}

Thus, the probability that a car that comes into the garage needs both an oil change and a tire rotation is \frac{12}{35}.

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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