Can someone help me on all 3 please?

The sum of the digits of a given two digits the new numbers is 5 .if the digits are reversed, the new number is reduced by 27 .

sleet_krkn [62]

Answer:. The numbers are 41 and 14

Step-by-step explanation: X and Y represent the digits. In the Tens place, the digit has 10× its base value. Therefore we can set up equations to model the information given:

10x+y = 10y + x +27

X + Y = 5

y =5-x rewritten to substitute for y

10x + 5-x = 10(5-x)+x +27

Distribute and then combine like terms:

9x +5 = 50 - 9x +27

Add 9x to both sides; subtract 5 from both sides.

9x +9x = 50+27-5

18x = 72 Combine like terms. Then divide both sides to solve for x.

x = 4

4+y=5 Substitute 4 for x; solve for y.

y=1

Substitute values of x and Y into the original equation and check.

40 +1 = 10 +4 + 27

41 = 14+ 27

True! 41=41

The numbers are 41 and 14.

5 0

3 years ago

Is the answer is 60 ? I'm so unsure let me know

FinnZ [79.3K]

Perimeter of this triangle

= (8 + 9 + 13) units

= 30 units

5 0

3 years ago

What value of c makes the equation true? (PLEASE HELP, and look at the picture)

Cloud [144]

Answer:

$\displaystyle c = 8$

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \frac{3}{6} = \frac{4}{c}$

Step 2: Solve for c

Simplify [Reduce]: $\displaystyle \frac{1}{2} = \frac{4}{c}$
[Multiplication Property of Equality] Cross-multiply: $\displaystyle c = 8$

8 0

3 years ago

Read 2 more answers

Suppose that 2 ≤ f '(x) ≤ 3 for all values of x. what are the minimum and maximum possible values of f(5) − f(1)?

zzz [600]

Assuming $f$ is differentiable over the interval (1, 5), by the mean value theorem we know that there is some $1$ such that

$f'(c)=\dfrac{f(5)-f(1)}{5-1}$

We're given that $2\le f'(x)\le3$ for all $x$ , so

$2\le\dfrac{f(5)-f(1)}4\le3\implies8\le f(5)-f(1)\le12$

that is, the minimum possible value is 8, and the maximum possible value is 12.

8 0

3 years ago

Find the Expression OF this equation. c/3 / ac/4 QUESTION C

Fiesta28 [93]

Answer:

See below

Step-by-step explanation:

$(a) \: \: x = \frac{c}{3} \\ \\ \implies \: {x}^{2} = { \bigg( \frac{c}{3} \bigg) }^{2} \\ \\ \bold{\implies \: {x}^{2} = \frac{ {c}^{2} }{9} } \\ \\ (b) \: \: x + y = \frac{c}{3} + \frac{ac}{4} \\ \\\implies \: \bold{x + y = \frac{4c + 3ac}{12} } \\ \\ \frac{xy}{z} = \frac{ \frac{c}{3} \times \frac{ac}{4} }{ \frac{ {a}^{2} }{2c + 1} } \\ \\ = \frac{ \frac{ac ^{2} }{12} }{ \frac{ {a}^{2} }{2c + 1} } \\ \\ = \frac{a {c}^{2} }{12} \times \frac{2c + 1}{ {a}^{2} } \\ \\ \implies\bold{\frac{xy}{z} = \frac{ {c}^{2}(2c + 1) }{12a} }$

8 0

2 years ago