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Ronch [10]
3 years ago
9

Eva and her grandchildren went into a bakery and where they sell cookies for $0.50 each and brownies for $2.25 each. Reba has &a

mp;15 and must buy a minimum of 9 cookies and brownies altogether. If she decided to buy 5 cookies, determine the maximum number of brownies she could buy.
Mathematics
1 answer:
irinina [24]3 years ago
4 0

Reba could buy a maximum of 5 brownies.

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Michael went shopping at the mall for a pair of Nike sneakers. The Nike store is giving him a 10% student discount. If the origi
Art [367]

Answer:

When discounted 10% you will pay 198$.

220-22=198$

5 0
3 years ago
Read 2 more answers
Let a=(?2,1,2, b=(?1,2,4, and p=(k,k,k. the vector from a to b is perpendicular to the vector from a to p when k =
prohojiy [21]
Vector a = (2, 1, 2)
Vector b = (1, 2, 4)
Vector p = (k, k, k)

Vector a to vector b = vector b - vector a = (1, 2, 4) - (2, 1, 2) = (1 - 2, 2 - 1, 4 - 2) = (-1, 1, 2)
Vector a to vector p = vector p - vector a = (k, k, k) - (2, 1, 2) = (k - 2, k - 1, k - 2)

Vector a to b is perpendicular to vector a to p if the dot product of vector a to vector b and vector a to vector p is equal to zero.
i.e. (-1, 1, 2) . (k - 2, k - 1, k - 2) = 0
-1(k - 2) + (k - 1) + 2(k - 2) = 0
-k + 2 + k - 1 + 2k - 4 = 0
2k -3 = 0
2k = 3
k = 3/2
6 0
3 years ago
Graph the function represented in the table on the coordinate plane.
Lena [83]

Step-by-step explanation:

We are given the co-ordinates,

x : -2, -1, 0, 1, 2

y : 8, 5, 2, -1, -4

According to the graph, we see that this function represents a straight line.

The general form of the straight line is y = mx + c, where m is the slope and c is the y-intercept.

So, taking any two points we will find the equation of the straight line.

Consider, (0,2) and (1, -1). Now, slope is given by,

m = \frac{-1-2}{1-0}

i.e. m = -3

Now, we will find the y-intercept of this equation using (0,2) and m = -3,

i.e. y = -3x + c

i.e. 2 = c

Hence, the equation of the straight line is y = -3x + 2.

6 0
4 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
4 years ago
14/219:13 AM
katrin [286]

Answer:

48 quarts = 12 gallons

Step-by-step explanation:

4 0
3 years ago
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