If tan 0=3/4 find csc0

Mathematics

1 answer:

jasenka [17]3 years ago

8 0

Answer:

tanθ = 3/4 p/b

using Pythagoras theorem

H² = P² + b²

H² = 3²+ 4²

H² = 25

H = 5

cosθ = B/H = 4/5

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Can u pls give a clear explanation & word it out how u got the answer without using big words. Thank u

gizmo_the_mogwai [7]

We can rewrite the squared in two ways.

The first way is to rewrite it as a multiplication, this is:

$(y-6)^2=(y-6)(y-6)$

The second way to rewrite the squared is by using the formula for this kind of product:

$(y-6)^2=y^2+2(-6)(y)+(-6)^2$

Once again we can find the final result using each of the options given in part A, for the first option we have:

$\begin{gathered} (y-6)^2=(y-6)(y-6) \\ =y^2-6y-6y+36 \\ =y^2-12y+36 \end{gathered}$

For the second option we have:

$\begin{gathered} (y-6)^2=y^2+2(-6)(y)+(-6)^2 \\ =y^2-12y+36 \end{gathered}$

No matter which way we choose the answer for the squared is:

$y^2-12y+36$

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shusha [124]

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krek1111 [17]

So the image consists of 1 rectangle and half a circle.

Rectangle - 12*19 = 228
Half a circle - $\pi r^2 = \pi 6^2 = 36 \pi/2 = 18 \pi$

In the end there are 2 rectangles (2*228 = 456) and 1 full circle (18*2 = 36), which makes the shaded area 456 ft and 36 $\pi$