What did Shah jahan name the Delhi

Mathematics

1 answer:

quester [9]3 years ago

8 0

Answer:

Mehru

Step-by-step explanation:

because

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In triangle ABC, which side is the longest if these are the measures of the angles? m∠A = 60°, m∠B = (3x − 2)°, m∠C = (2x + 7)°

gogolik [260]

Answer:

Step-by-step explanation:

First, let's find m∠B and m∠C by solving for x. Since the sum of interior angles in a triangle is 180°, we know that:

60 + 3x - 2 + 2x + 7 = 180

5x + 65 = 180

5x = 115

x = 23° so m∠B = 3(23) - 2 = 67° and m∠C = 2(23) + 7 = 53°. The longest side of a triangle is always opposite to the largest angle of the triangle, and since m∠B is the largest, we know that the side opposite to ∠B is the longest. That side is AC.

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2 years ago

In 60 words or fewer, write what you think the term economy means.

fredd [130]

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Step-by-step explanation:

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2 years ago

Answer choices are <br> A. 119 <br> B. 21<br> C. 39 <br> D. 40

pshichka [43]

The answer c
Btw don’t open the guy from above they track you

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%202%20%20%5Csin%28%20%5Calpha%20%29%20-%20%20%20%5Ccos%28%20%5Calpha%20%29%20%20%3D%202%20%5C

mr Goodwill [35]

$2\sin\alpha-\cos\alpha=2$

Consider the substitution $\tan\dfrac\alpha2=\beta$ . Then by the double angle identities we get

$\sin\alpha=2\sin\dfrac\alpha2\cos\dfrac\alpha2$

$\cos\alpha=\cos^2\dfrac\alpha2-\sin^2\dfrac\alpha2$

We also have

$\tan\dfrac\alpha2=\beta\implies\begin{cases}\sin\dfrac\alpha2=\dfrac\beta{\sqrt{1+\beta^2}}\\\\\cos\dfrac\alpha2=\dfrac1{\sqrt{1+\beta^2}}\end{cases}$