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hram777 [196]
3 years ago
6

The box plots compare the number of students in Mr. Ishimoto’s classes and in Ms. Castillo’s classes over the last two semesters

. A number line goes from 22 to 42. Mrs. Ishimoto's class's whiskers range from 28 to 40, and the box ranges from 31 to 35. A line divides the box at 33. Mr. Castillo's class's whiskers range from 24 to 38, and the box ranges from 30 to 34. A line divides the box at 31. Which statement is true about the box plots? Select three options.
Mathematics
2 answers:
otez555 [7]3 years ago
3 0

Answer: B,D,E

Step-by-step explanation:

yan [13]3 years ago
3 0

Answer:

2, 4, 5

Step-by-step explanation:

:)

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On Monday you sent x number of text messages. On Tuesday you sent twice as many. On Wednesday you sent 12 more texts than you se
Lady bird [3.3K]

Answer:

Expression representing number of text messages sent on Tuesday = 2x , where x = text messages sent on Monday

Step-by-step explanation:

Let number of messages sent on Monday = x

So, number if messages sent on Tuesday = 2 times x = 2x

Number of texts sent on Wednesday = 12 more than texts sent on Tuesday = 2x + 12

Number of texts sent on Thursday = Half the texts sent on Wednesday =   1/2 (2x + 12) = x + 6

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3 years ago
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A bag has 7 red marbles, 8 blue marbles, and 5 purple marbles. Rachel draws a marble from the bag without looking.
Fiesta28 [93]
First you would add all the marbles together because you need to know how many are in the bag in total.

7 + 8 + 5 = 20

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8 / 20

And there's your answer.
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Solution for 8.5+4(1-2.5k)= -25.5
Nonamiya [84]
The solution is k=19/5
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3 years ago
HELP! HELP! SAVE ME FROM THIS NIGHTMARE!!!
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Answer: x ≥ 6

Step-by-step explanation:

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Calculate the mean deviation by median (by using the mid-point(x) of leaf weights. b) A fair die is rolled. Find the probability
SVETLANKA909090 [29]

Answer:

hello attached below is the required table that is missing and the completed table as well

A) mean deviation = 0.1645

B) 2/3

Step-by-step explanation:

From the table we calculated the midpoint value (x) and c.f

N = 27

median class = 2.35 to 2.45

median = l + [ (N/2) - cf / F ] * H

             = 2.35  + [ (13.5 - 13) / 6 ] *0.1 = 2.3583

hence mean deviation by median

= summation of  fi |xi -M| / summation of fi

= 4.4417 / 27 = 0.1645

B ) probability of getting an odd number or prime number or both

the probability of an odd number = 1/2

also the probability of an even number = 1/2

while the probability of getting neither of them = 1/3

hence the probability of getting odd or prime or both

= 1/2 + 1/2 - 1/3 = 2/3

6 0
3 years ago
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