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allochka39001 [22]
3 years ago
6

Jimmy will need 85,500 to attend the College of his choice if he and his family save the same amount each month for 3 years what

is the minimum monthly amount that should save
Mathematics
2 answers:
Gre4nikov [31]3 years ago
5 0
85,500 / 3 years = 28,500 per year
28,500 per year / 12 months in a year = 2,375

They should save 2,375 per month
schepotkina [342]3 years ago
4 0
The family need to save minimum $2375 for each month. Hoped it help!
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The circle graph shows the results of a survey by a bakery on which of their new products 105 customerspreferred most. How many
Katen [24]

If 105 customers were the total, and 35% prefers cake, we must calculate 35% of 105, then we must do 105 multiplied by 35%, we can doit transforming the 35% in the fraction notation:

35\%=\frac{35}{100}

And the multiplication

105\cdot\frac{35}{100}=36.75

Therefore, if we round it to the nearest whole number, the number of customers that prefer cake is 37.

37 customers prefer cake.

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Please help maths homework
kaheart [24]

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Step-by-step explanation:

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3 years ago
For the following exercises, determine whether the relation is a function.
elixir [45]

Answer:

The given relation $\{(a, b),(c, d),(e, d)\}$ is a function.

Step-by-step explanation:

A relation $\{(a, b),(c, d),(e, d)\}$ is given.

It is required to determine whether the given relation is a function.

To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.

Step 1 of 1

The given relation is {(a, b),(c, d),(e, d)}.

The set of the first components of each ordered pair is called the domain.

From the relation, the domain is {a, c, e}.

The set of the second components of each ordered the range.

From the relation, the range is {b, d, d}.

The given relation is a function. But it is not a one-to-one function.

7 0
2 years ago
A black bear has a tail 190 mm long.How many cm is that?
GarryVolchara [31]

Answer:19

Step-by-step explanation:

Divide 190 by 10

7 0
3 years ago
Read 2 more answers
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
2 years ago
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