3 years ago

State the domain and range of the given relation

Mathematics

1 answer:

GuDViN [60]3 years ago

5 0

Answer:

work is shown and pictured

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(a2 + 2a + 1)(a + 1)

GrogVix [38]

$(a^2+2a+1)(a+1)=(a^2)(a)+(a^2(1)+(2a)(a)+(2a)(1)+(1)(a)+(1)(1)\\\\=a^3+a^2+2a^2+2a+a+1=\boxed{a^3+3a^2+3a+1}$

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3 years ago

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Solve. 12a−12=−11 Enter your answer in the box. a =

madreJ [45]

Answer:

a=1/12

Step-by-step explanation:

12a-12=-11

12a=-11+12

12a=1

a=1/12 or .0833333 repeating

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3 years ago

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Perform the indicated operations, and then answer the question.

marin [14]

Answer:

i pretty sure its C.

Step-by-step explanation:

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3 years ago

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Please help

ololo11 [35]

Answer:

Step-by-step explanation:

3 + 5 = 8

3 0

3 years ago

Pls help me...........

schepotkina [342]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sin²x = 1 - cos²x

sinx = $\sqrt{1-cos^2x}$

note that cosΘ = $\frac{6}{10}$ = $\frac{3}{5}$

sinΘ = $\sqrt{1-(3/5)^2}$

= $\sqrt{1-\frac{9}{25} }$

= $\sqrt{\frac{16}{25} }$ = $\frac{4}{5}$

6 0

4 years ago