Please help

In a survey conducted by a website, employers were asked if they had ever sent an employee home because they were dressed inappr

castortr0y [4]

Answer:

$z=\frac{0.353 -0.333}{\sqrt{\frac{0.333(1-0.333)}{2759}}}=2.23$

$p_v =P(z>2.23)=0.0129$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of more than one-third of employers have sent an employee home to change clothes is higher than 1/3 or 0.333.

Step-by-step explanation:

Data given and notation

n=2759 represent the random sample taken

X=974 represent the people saying that they had sent an employee home for inappropriate attire

$\hat p=\frac{974}{2759}=0.353$ estimated proportion of people saying that they had sent an employee home for inappropriate attire

$p_o=0.333$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than one-third of employers have sent an employee home to change clothes.:

Null hypothesis: $p \leq 0.33$

Alternative hypothesis: $p > 0.33$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.353 -0.333}{\sqrt{\frac{0.333(1-0.333)}{2759}}}=2.23$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed the p value would be:

$p_v =P(z>2.23)=0.0129$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of more than one-third of employers have sent an employee home to change clothes is higher than 1/3 or 0.333.

4 0

3 years ago

Help!! what is the distance between points Q and S

Schach [20]

Answer:

6 units

Step-by-step explanation:

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3 years ago

Read 2 more answers

PLEASE HELP GEOMETRY !!!!!

statuscvo [17]

Answer:

x = 11.5

Step-by-step explanation:

$\sin \: 35 \degree = \frac{x}{20} \\ \\ x = 20 \sin \: 35 \degree \\ \\ x = 11.471528727 \\ \\ x = 11.5$

8 0

3 years ago

A recipe calls for 3 3/4 cups of milk. If the recipe is doubled, how much milk is needed?

denpristay [2]

Initially, milk needed = 3 3/4 = 15/4

If it doubles, 15/4 * 2 = 30/4 = 15/2 in fraction form

OR 7.5 in decimal form

OR 7 1/2 in mixed form

5 0

4 years ago

How do you calculate volume of a triangular prism?

kirill [66]

Hello there, and thank you for asking your question here on brainly.

To find the volume of a triangular prism, you have to use the long formula shown below. (v)

1/4h √-a^4 + 2 (ab)² + 2 (ac)² - b^4 + 2 (bc)² - c^4.

Hope this helped!! ☺♥

4 0

3 years ago