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Irina-Kira [14]
3 years ago
8

Two carts collide, similar to our in-class examples. Cart A has a mass of 2 kg, and is moving to the right at 4 m/s when it bump

s into cart B (5 kg), which is moving left at 3 m/s. If the carts stick together after the collision, how fast are they moving?
Mathematics
1 answer:
Triss [41]3 years ago
5 0

Answer: 1 m/s to the left

Step-by-step explanation: Considering momentun conservation, this is as follow:

PA+PB= Constant

PA= 2 Kg * 4 m/s to the rigth

PB= 5 Kg* 3 m/s to the left

after collision the two mass go together so the PA+B = Vfinal (mA+mB)= Vfinal (2 kg +5 kg), the momentum conservation is then

PA-PB=8-15=-7 = Vfinal (7kg)

Vfinal= -7/7 m/s=-1 m/s

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Step-by-step explanation:

Given that by using the distributive property to match the given equivalent expressions.

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7(4+x) =(7)(4)+(7)(x)

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4) Given expression is 7(-4-x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

7(-4-x) =(7)(-4)+(7)(-x)

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