x= 3+√5/4,3-√5/4
Step-by-step explanation:
1.In general, given ax^2+bx+c=0, there exists two solutions where:
x= -b+√b^2 - 4ac/2a, -b-√b^2-4ac/2a
2.In this case, a=4, b=-6 and c=1.
x=6+√(-6)^2-4×4/2×4, 6-√(-6)^2-4×4/2×4
3.Simplify.
x=6+2√5/8, 6-√5/8
4.Simplify solutions.
x=3+√5/4, 3-√5/4
?.....OH these are steps xD
a. and b.
<span>P(1,2,0), Y(-2,3,0), R(3,4,0), and A (2,1,5).
c. and d.</span><span>
</span>P(3,6,-3), Y(0,7,-3), R(5,8,-3), and A (4,5,2).
This is easy. All we have to do is 0.2 minus 0.02 which is 0.18 This is because the 2 next to the 2 in the hundredths place is a 2 in the tenths place. I hope this helps!
Answer:
x+
Step-by-step explanation: