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2 years ago

Please help Faaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaast 2x ≤ − 2/7 (8x + 8)

Mathematics

1 answer:

soldi70 [24.7K]2 years ago

5 0

Answer:

Step-by-step explanation:

<u>First of all multiply through by 7</u>

We have

<u>Expand the terms in the bracket</u>

That's

<u>Add 16x to both sides</u>

That's

<u>Divide both sides by 30</u>

We have the final answer as

Hope this helps you

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an entertainment firm offers several DJ choices and light show that range in price based on the rental time period. the DJ's cos

Mnenie [13.5K]

Answer:

219 + 159 <= x <= 369 + 309

378 <= x <= 678

Step-by-step explanation:

4 0

1 year ago

15 POINTS!!!!!! PLEASE HELP!!The length of a rectangle is four times its width. If the perimeter is at most 130 centimeters, wha

marin [14]

Here is the information we have:

1. The perimeter is at most 130 cm.
2. The length of the rectangle is 4 times the width.
We can let l stand for length and w for width.

The formula for the perimeter of a rectangle is 2l + 2w.
We have to change the formula a bit.
The length of this rectangle is going to be 4 times the width
So, replace 2l with 2(4w).

Then make this equation equal to 130.

2(4w) + 2w = 130 ; Start
8w + 2w = 130 ; Distribute the 2 across the 4w
10w = 130 ; Combine the like terms 8w and 2w
w = 13 ; Divide both sides by the coefficient of w. Which is 10

8 0

2 years ago

If you buy 3 apples worth 0,65$ each with a 10$ note, how much change are you left with ?

Alex

$10.00 - 3($0.65)
$10.00 - $1.95
= $8.05

3 0

3 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

1 year ago

Subtract 60 from the sum of 8e and 20 when e=7

Diano4ka-milaya [45]

Answer:

Subtract 60 from the sum of 8e and 20 when e=7

8e +20

8(7) + 20

56+20=76

76-60=16

8 0

2 years ago