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nlexa [21]
4 years ago
9

Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes. What

was the submarine's depth relative to sea level after the first minute? Enter your answer as a fraction, in simplest form, in the box.
Mathematics
2 answers:
SashulF [63]4 years ago
8 0

Answer:

-3/20

Step-by-step explanation:

Helga [31]4 years ago
4 0

Answer:

\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles

Step-by-step explanation:

Starting at sea level, a submarine descended at a constant rate to a depth of −4/5 mile relative to sea level in 3 minutes.

Total time = 3 minutes

\texttt{Total depth descended in 3 minutes =}-\frac{4}{5}miles

We need to find what was the submarine's depth relative to sea level after the first minute,

\texttt{Depth descended in per minute =}\frac{-\frac{4}{5}}{3}=-\frac{4}{15}miles

\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}\times 1=-\frac{4}{15}miles\\\\\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles

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Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B
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Answer:

x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)

Step-by-step explanation:

we are given that x^3-9x+2x^2-18

w are sked to step by step factorise the above polynomial

\left(x^3+2x^2\right)+\left(-9x-18\right)

-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)

-9x-9\cdot \:2

-9\left(x+2\right)

\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)

-9\left(x+2\right)+x^2\left(x+2\right)

\left(x+2\right)\left(x^2-9\right)

x^2-9:\quad \left(x+3\right)\left(x-3\right)

x^2-9

\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2

=x^2-3^2

\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)

x^2-3^2=\left(x+3\right)\left(x-3\right)

Hence

x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)

a) The jay mistake was he did not factorise  x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be  [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)

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