Answer:
A
Step-by-step explanation:
11/4 hours on the first day
21/4 hours on the second
21-11=10
10/4 hours or 2 2/4
(5,24)
- The two areas are the same.
- To find the area, we multiply the side lengths. Y=area
Rectangle 1: side lengths 4 and (x+1)
y=4(x+1)= 4x+4
Rectangle 2: side lengths 3 and (2x-2)
y=3(2x-2)= 6x-6
- Since the two areas are same, we can conclude that
4x+4=6x-6
-2x=-10, x=5
- Since x is 5, we can plug it into the equations to find y.
Option 1 with rectangle 1: y=4(5)+4, y=24
Option 2 with rectangle 2: y=6(5)-5, y=24
I graphed the linear equation on desmos.
V is the 3D region enclosed by S.
div(F)= <span>∂(x)/∂x + ∂(y)/∂y + ∂(10)/∂z = 2
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<span>∫ = ∫∫∫ [V] div(F) dV = 2 ∫∫∫ [V] dV
Using cylindrical coords, ( rcos(θ), y, rsin(θ) ), dV=rdrdθdy
∫ = 2 ∫∫∫ rdrdθdy, [r=0,1], [θ=0,2π], [y=0,7−rcos(θ)] = 14π (easily integrated)</span><span>
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