Please HELP me!! Will choose brainliest (:

Mathematics

1 answer:

Rzqust [24]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

There are several ways to go at this.

My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.

Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.

You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.

(((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0

The value of h(5) is zero, so x-5 is a factor of h(x).

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Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they

inysia [295]

You have two unknown rates, so we need to develop two equations to solve for these unknowns (based on the information given on the problem statement):

5x + 10y = 725
x + y = 100

By substitution, we get:

5x + 10(100 - x) = 725
5x + 1000 - 10x = 725
-5x = 725 - 1000
-5x = -275
x = -275/-5 = 55

100 - 55 = 45

Thus:
The mechanic who worked for 5 hours charged his time at $55/hr, and the mechanic who worked for 10 hours charged his time at $45/hr.

To verify, plug and chug the results back into the original equations:

5(55) + 10(45) = 725
275 + 450 = 725
725 = 725 [OK]

55 + 45 = 100 [OK]

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sergeinik [125]