I believe that the answer is: A all integers from 10 to 50 , inclusive
Answer:
$500 would be better, for 4 months only...
Answer:
a(n)=1+(n-1)(-3)
Step-by-step explanation:
Notice there's a common difference of d=-3.
If we use the formula a(n)=a1+(n-1)d to find the nth term given the first term and the common difference, we will see that the function that describes the arithmetic sequence as a(n)=1+(n-1)(-3)
Hey there! :D
So you're wondering if you can make a new ten in this problem, right? Well, lets find out! We can simply do<span> 59 + 17 = 59 + 1 + 16 = 60 + 16 = 76. When we did 59 + 1, that is a new ten then we added to 16. So yes, we did make a new ten in this problem. </span>
<span>Hope it helps! ;)</span>
Answer: (9ab^2+c^3)(9ab^2-c^3)
Step-by-step explanation:
81a^2b^4-c^6
(9ab^2)^2-(c^3)^2
(9ab^2+c^3)(9ab^2-c^3)
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤
