What is the distance around a triangle that has sides measuring 21/8 feet, 31/2 feet and 21/2 feet?
1 answer:
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Answer:
y = 3/4x - 5
Step-by-step explanation:
An equation of a line can be written in slope-intercept form:
y = mx + b
where m is the slope and b is the y-intercept.
Let's plug in what we know.
The slope is 3/4.
y = 3/4x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.
-2 = 3/4(4) + b
To find b, multiply the slope and the input of x(4)
-2 = 3 + b
Now, subtract 3 from both sides to isolate b.
-5 = b
Plug this into your standard equation.
y = 3/4x - 5
This is your equation. It has a slope of 3/4, and passes through (4, -2)
Hope this helps!
