Question

What is the distance around a triangle that has sides measuring 21/8 feet, 31/2 feet and 21/2 feet?

Answer 1

Add all of the sides together. Make sure to use a common denominator because you are adding fractions. Don't forget your unit label (feet)
$\frac{21}{8}$ + $\frac{31}{2}$ + $\frac{21}{2}$
$\frac{21}{8}$ + $\frac{124}{8}$ + $\frac{84}{8}$
$\frac{229}{8}$ feet