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Verdich [7]
3 years ago
14

What is the distance around a triangle that has sides measuring 21/8 feet, 31/2 feet and 21/2 feet?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0
Add all of the sides together. Make sure to use a common denominator because you are adding fractions. Don't forget your unit label (feet)
\frac{21}{8} + \frac{31}{2} + \frac{21}{2}
\frac{21}{8} + \frac{124}{8} + \frac{84}{8}
\frac{229}{8} feet

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solve x

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x = 3.2/4 = 0.8

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