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wariber [46]
3 years ago
6

Which percent is equivalent to 2.5? 2.5% 25% 250% 2,500%

Mathematics
2 answers:
zaharov [31]3 years ago
6 0

Answer:

250%

Step-by-step explanation:

jarptica [38.1K]3 years ago
5 0

Answer:

c

Step-by-step explanation:

You might be interested in
At an art exhibition there are 12 paintings of which 10 are original. A visitor selects a painting at random and before decides
Reika [66]

Answer:

a) 0.8333

b) 0.75

c) 0.8181 or 0.9090

Step-by-step explanation:

a)

The probability the visitor selects an authentic painting is  

10/12 = 0.8333

b)

Since the opinion of the expert does not depend on your choice, the events are <em>independent</em>, so the probability that the expert says is authentic and it really is, is

0.8333*0.9 = 0.75

c)

If the expert decides the painting is a copy and it is not, then there are 11 paintings of which 9 are authentic, so the probability the visitor selects a new original painting is

9/11= 0.8181

If the expert decides the painting is a copy and it is, then there are 11 paintings of which 10 are authentic, so the probability the visitor selects a new original painting is

10/11= 0.9090

8 0
4 years ago
What is the answer to this question? Write an expression in simplest form for the perimeter of a right triangle with leg lengths
blagie [28]

Answer:

Step-by-step explanation:

Since the length of both legs of the right angle triangle are given, we would determine the hypotenuse, h by applying Pythagoras theorem which is expressed as

Hypotenuse² = one leg² + other leg²

Therefore,

h² = (3a)³ + (4a)³

h² = 27a³ + 64a³

h² = 91a³

Taking square root of both sides,

h = √91a³

The formula for determining the perimeter of a triangle is expressed as

Perimeter = a + b + c

a, b and c are the side length of the triangle. Therefore, the expression for the perimeter of the right angle triangle is

√91a³ + (3a)³ + (4a)³

= √91a³ + 91a³

7 0
3 years ago
based only on the inormation given in the diagram, which congruence theorems or postulates could be the given as reasons why abc
Fudgin [204]

Answer: 1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.

3. SAS can be a reason to show given triangles are congruent as there are  two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].

4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

5. AAS  cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.

6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.

HOPE THIS HELPS

6 0
3 years ago
in their last game the new england patriots scored 9 points in the first half they scored two times the points in the first half
svetoff [14.1K]

Answer:

The correct answer would be 3:5

Step-by-step explanation:

It is asking about the second half to the total number of points scored.

first half : 9

second half : 15

9:15 = 3:5

5 0
3 years ago
rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
OleMash [197]

Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of  y⁴  is '-17'</em>

<em>   </em>

5 0
4 years ago
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