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ki77a [65]
4 years ago
7

Brandy wants to buy a digital camera that costs $300.Suppose she saves $15 dollars each week.In how many weeks will she have eno

ugh money for the camera?
Mathematics
2 answers:
s2008m [1.1K]4 years ago
7 0

You have to divide 300 with 15, the answer to that is: 300/15=20. However, if she starts saving this week (counting as a first), she will have enough money in 19 weeks after the first week, she needs 20 weeks to save the money.

andrey2020 [161]4 years ago
5 0
20 weeks should give him just enough.

By either writing and solving a simple equation (15w=300) or dividing by 15, you can figure out how many amounts of 15 would need to be saved to get 300.
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How many committees of 4 boys and 3 girls<br> can be formed from a class of 6 boys and 7<br> girls?
VLD [36.1K]

Answer:

525

Step-by-step explanation:

This is a question involving combinatorics

The number of ways of choosing a subset k from a set of n elements is given by {n \choose k} which evaluates to \frac{n!}{k!(n-k)!}

n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1

For example,

4! = 4 x 3 x 2 x 1 = 24

3! = 3 x 2 x 1 = 6

Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is

{6 \choose 4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4!2!}

Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1  is nothing but 4!

So the numerator can be re-written as 6 x 5 x (4!)

We can rewrite the expression \frac{6!}{4!2!} \text{ as } \frac{6.5.4!}{4!2!}

Cancelling 4! from both numerator and denominator gives us the result

as  (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys

For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by

{7 \choose 3} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!4!}

This works out to (7 x 6 x 5 )/(3 x 2 x 1)  (using the same logic as for the boys computation)

= 210/6 = 35

So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525

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