Answer:
Carter's coins could be;
3 of 5¢, 2 of 10¢, 1 of 25¢, and 1 of 50¢
Step-by-step explanation:
The available coin denominations are;
1¢ = 1 penny, 5¢, 10¢, 25¢, 50¢, and $1.00
Since the coins are more than $0.95, we can have;
5¢ × 3
10¢× 2
25¢× 1
50¢
Total = $1.00
That is his coins could have been 3 × 5¢, 2 × 10¢, 1 × 25¢, and 1 × 50¢, to make a total of 7 coins with an amount value of $1.00.
