Answer:
29520728184915396206153835295
Answer:
The sample size to obtain the desired margin of error is 160.
Step-by-step explanation:
The Margin of Error is given as
Rearranging this equation in terms of n gives
Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as
As n is given as 40 so the new sample size is given as
So the sample size to obtain the desired margin of error is 160.
The first, second one because they synchronization are proved to equally cause them to be similar
3.22$ because your originally spending 35$ so the added 3.22$ makes up 38.22$