Answer:
run the code to see where the error is
Explanation:
<span>Go paperless.
Use natural lighting.
Grow trees nearby.
Reduce, reuse, and recycle.
Carpool.
</span>
Answer:
getline(cin, address);
Explanation:
Given
String object: address
Required
Statement that reads the entire line
The list of given options shows that the programming language is c++.
Analysing each option (a) to (e):
a. cin<<address;
The above instruction will read the string object until the first blank space.
Take for instance:
The user supplied "Lagos state" as input, only "Lagos" will be saved in address using this option.
b. cin address:
This is an incorrect syntax
c. getline(cin,address);
Using the same instance as (a) above, this reads the complete line and "Lagos state" will be saved in variable address
d. cin.get(address);
address is created as a string object and the above instruction will only work for character pointers (i.e. char*)
<em>From the above analysis, option (c) is correct.</em>
First you go to the 3 dots neer the x you pres it thin you go to downloads and it shod be ther i hop i help if so make me the branliy
Answer:
public class MagicSquare {
public static void main(String[] args) {
int[][] square = {
{ 8, 11, 14, 1},
{13, 2, 7,12},
{ 3, 16, 9, 6},
{10, 5, 4, 15}
};
System.out.printf("The square %s a magic square. %n",
(isMagicSquare(square) ? "is" : "is not"));
}
public static boolean isMagicSquare(int[][] square) {
if(square.length != square[0].length) {
return false;
}
int sum = 0;
for(int i = 0; i < square[0].length; ++i) {
sum += square[0][i];
}
int d1 = 0, d2 = 0;
for(int i = 0; i < square.length; ++i) {
int row_sum = 0;
int col_sum = 0;
for(int j = 0; j < square[0].length; ++j) {
if(i == j) {
d1 += square[i][j];
}
if(j == square.length-i-1) {
d2 += square[i][j];
}
row_sum += square[i][j];
col_sum += square[j][i];
}
if(row_sum != sum || col_sum != sum) {
return false;
}
}
return d1 == sum && d2 == sum;
}
}
