Answer:
A. VLOOKUP
Explanation:
VLOOKUP is an Excel function to look up data in a table organized vertically. VLOOKUP supports approximate and exact matching, and wildcards (* ?) for partial matches. Lookup values must appear in the first column of the table passed into VLOOKUP.
Purpose
Lookup a value in a table by matching on the first column
Return value
The matched value from a table.
Syntax
=VLOOKUP (value, table, col_index, [range_lookup])
Arguments
value - The value to look for in the first column of a table.
table - The table from which to retrieve a value.
col_index - The column in the table from which to retrieve a value.
range_lookup - [optional] TRUE = approximate match (default). FALSE = exact match.
Answer:
Computer scientists began building rudimentary games and simulations on mainframe computers in the 1950s and 1960s, with MIT's Spacewar! in 1962 being one of the first such games to be played with a video display. The first consumer-ready video game hardware arrived in the early 1970s, with the Magnavox Odyssey, the first home video game system, and the first arcade video games from Atari, Computer Space and Pong, the latter of which was later transformed into a home console version. Pong's success in arcades and at home prompted numerous firms to create clones of the game, resulting in a market contraction in 1978 owing to oversaturation and a lack of innovation.
The answer that is a record in a relational database is called; A row
<h3>What is a record in relational database?</h3>
In relational databases, a record is defined as a group of related data held within the same structure. Furthermore, we can say that a record is a grouping of fields within a table that reference one particular object.
Now, in relational database, a row is called a record because each row, contains a unique instance of data or key for the categories defined by the columns.
Read more about Relational Database at; brainly.com/question/13262352
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Answer:
Answer explained
Explanation:
From the previous question we know that while searching for n^(1/r) we don't have to look for guesses less than 0 and greater than n. Because for less than 0 it will be an imaginary number and for rth root of a non negative number can never be greater than itself. Hence lowEnough = 0 and tooHigh = n.
we need to find 5th root of 47226. The computation of root is costlier than computing power of a number. Therefore, we will look for a number whose 5th power is 47226. lowEnough = 0 and tooHigh = 47226 + 1. Question that should be asked on each step would be "Is 5th power of number < 47227?" we will stop when we find a number whose 5th power is 47226.
