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3 years ago

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jen butler has beeb pricing speed-pass train fares for a group trip to new york. three adults and four children must pay $80. tw

o adults and three children must pay $57. find the price of adults ticket's and the price of a child's ticket

1 answer:

Degger [83]3 years ago

3 0

Answer:

Adult price is: $12

Children price is: $11

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If MN=14, NO=11, and QR=27, find the length of PQ. Round your answer to the nearest tenth if necessary. Figures are not necessar

allsm [11]

Answer:

PQ = 34.4

Step-by-step explanation:

First, we know that the angles in a triangle add up to 180 degrees. Therefore, angle M = 48 and angle R = 74

Next, because there is a corresponding angle in each triangle, they are similar. This means that the ratios between corresponding sides are the same. For example, the side opposite angle O (MN) over the side opposite angle R (PQ) is equal to the side opposite angle N (OM) over the side opposite angle Q (RP)

This can be written as MN/PQ = OM/RP. Note that both the numerators are on the same triangle, and MN and PQ correspond, as well as OM and RP.

We are given MN, NO, and QR. Because NO is opposite a 48 degree angle (angle M) as well as QR (angle P), we can say that NO/QR = another ratio of a pair of corresponding sides. Because we want to find PQ, and both PQ and MN are opposite 74 degree angles, we can say that

NO/QR = MN/PQ

Thus,

11/27 = 14/PQ

multiply both sides by PQ to remove a denominator

PQ * 11/27 = 14

multiply both sides by 27 to remove the other denominator

PQ * 11 = 14 * 27

divide both sides by 11 to isolate the PQ

PQ = 14 * 27 /11

PQ = 34.4

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A Circus charges two dollars and 50 Cent for kids tickets and six dollars for adults tickets. Last weekend, twice as many kids a

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3 years ago

A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban

zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be $x.$

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to $x.$

$\frac{36}{52} =\frac{22}{x}$

<em>By cross multiplying we get:</em>

<em /> $36x=1144$ <em />

<em>Dividing both sides by 36 we get:</em>

$x=31\frac{7}{9} .$

<em>Hence, the width of sign is </em> $31\frac{7}{9}$ <em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

$Area\ of\ banner=36\times 52$

$Area\ of\ banner=1872\ square\ inches.$

Now, area of sign:

$Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.$

Now, to get the ratio of the area of the school banner to the area of the sign:

$1872:\frac{6292}{9}$

$=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}$

<em>On simplifying we get:</em>

$=\frac{4212}{1573}$

$=4212:1573.$

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

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