Question

I need help with this one math question please!

Answer 1

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

$\frac{x-5}{(x-5)(x+2)}$ × $\frac{x+2}{(x+4)(x-3)}$

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

$\frac{1}{(x+4)(x-3)}$ = $\frac{1}{x^2+x-12}$