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3 years ago

I need help with this one math question please!

Mathematics

1 answer:

den301095 [7]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

$\frac{x-5}{(x-5)(x+2)}$ × $\frac{x+2}{(x+4)(x-3)}$

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

$\frac{1}{(x+4)(x-3)}$ = $\frac{1}{x^2+x-12}$

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FinnZ [79.3K]

Answer:

y-(-20)=1(x-(-10))

Step-by-step explanation:

If you're really in college you should know this, but here's the explanation:

m= -9-(-20)

1-(-10)

= 11

m = 1

The equation is y-y^1=m(x-x^1)

Replace the y^1, m, and x^1 from the first point

You get y-(-20)=1(x-(-10))

Or simplify that into y+20=x+10

You can also simplify it more but I don't think you need that for that question

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3 years ago

Find the sum of the following infinite geometric series.

pishuonlain [190]

Answer is b hope this helps you

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3 years ago

X^lg(x)=100^x find x

Wittaler [7]

$x^lg(x)=100^x$

$X^lg(x)=100^x:x$ $|Solve \ for \ x|$

$|Use \ logarithms \ of \ both \ sides \ of \ the \ base \ 10|

$

$lg (x ^ lg (x)) = lg (100x)

$

$lg ^ 2 (x) = 2 + lgx$

$lg 2 ^ x-lg x -2 = 0$

$lg x = 2 x = 100$

$lg x = -1 x = \dfrac{1}{10} = 0.1$

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3 years ago

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Gelneren [198K]

X=7
I hope this helps

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