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kramer
3 years ago
9

Show that |3+10|=|3|+ |10|?

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0
|3+10|=|3|+|10|
|13|=|13|
13=13
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Pamela bought an electric drill at 85% of the regular price. She paid $32.89 for the drill. What was the regular price? (Round t
Stolb23 [73]
<span>38.69</span>

This is because
32.89/0.85 = 38.69
5 0
3 years ago
Cho tam giác ABC có diện tích= 105cm vuông. Trung tuyến AM và BN cắt nhau tại G.
joja [24]

Answer:

english pls.

Step-by-step explanation:

showing wrong transalation in transalate

5 0
2 years ago
3a+3b,for a=2 and b=4
il63 [147K]
3a + 3b, for a=2 and b=4 ... The first thing you'd do would be to plug the numbers in -

3 x 2 + 3 x 4 

Then multiply them -

6 + 12 

Then add - 

18.

So your answer should be 18.

5 0
3 years ago
Nathaniel works as a baker and makes several batches of muffins every morning. each batch requires 1 1/7 cups of sugar. for a la
kramer

The amount of sugar he will use is 5.22 cups of sugar, and the number of boxes needed to pack the muffins is 13.71 boxes.

<h3>How do we solve a word problem?</h3>

This word problem question can be solved as follows:

Amount of sugar he will use = 1  1/7 * 4 4/7 = 1.142857142857143 * 4.0.571428571428571 = 5.22 cups of sugar

Number of boxes needed to pack the muffins for the meeting = 4 4/7 * 3 = 4.0.571428571428571 * 3 = 13.71 boxes

Learn more about how to solve word problems here: brainly.com/question/13732946.

#SPJ1

8 0
2 years ago
A CBS News/New York Times opinion poll asked 1,190 adults whether they would prefer balancing the federal budget over cutting ta
nikklg [1K]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • 1,190 adults were asked, hence n = 1190
  • In fact 62% of all adults favor balancing the budget over cutting taxes, hence p = 0.62.

The mean and the standard error are given by:

\mu = p = 0.62

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.62(0.38)}{1190}} = 0.0141

The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.59 - 0.62}{0.0141}

Z = -2.13

Z = -2.13 has a p-value of 0.0166.

0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0
2 years ago
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