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zaharov [31]
2 years ago
8

7 over 12 minus 5 over 12 as a fraction in simplest form

Mathematics
2 answers:
s2008m [1.1K]2 years ago
4 0

Answer:

1 over 6

Step-by-step explanation:

7 - 5 = 2

2 over 12 can simplify into 1 over 6

poizon [28]2 years ago
3 0

Answer:

1/6

Step-by-step explanation:

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4 days ago, Emily blew up a balloon (that is a perfect sphere) to a radius of 5cm. Since then, the balloon has lost air and decr
Elan Coil [88]

Answer:

27/125

Step-by-step explanation:

3 0
3 years ago
The senate in a certain state is comprised of 51 republicans, 48 democrats, and 1 independent. How many committees can be formed
Sedaia [141]
17 since 51 goes into 3 17 times and 2 goes into 48 24 times and 17 is the largest number that can have 3 republicans and 2 democrats. The andwer would be 17 comittees,
5 0
2 years ago
express each of the following as product of its prime factors, giving your answer in expanded form. a) 24. b) 63. c) 84. d) 150​
Alborosie
To answer this question, you can use a factor tree, or the table thing (I forgot what it’s called.)
You divide the number by one of its PRIME factors, until there is only one left. The numbers you divided it by are written as shown.
Hope this helps. :)
3 0
3 years ago
Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

5 0
2 years ago
3a+2= -2n+3p solve for a
nataly862011 [7]

Answer:

Step-by-step explanation:

3a + 2 = -2n + 3p

3a = -2n + 3p - 2

a = (-2n+3p-2)/3

a = -2/3(n) + p - 2/3

8 0
3 years ago
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