Answer:
21.9°
Step-by-step explanation:
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
We solve this above question using the Sine rule
a/sin A = b/sin B
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.
Hence:
HI/∠J = JH/∠H
= 8/sin 90° = 1.9/sin ∠H
Cross Multiply
∠H = arc sin(sin 1.9 × 90/8)
∠H = 21.9°
Answer:
4.19
Step-by-step explanation:
Find the mean:

Find the standard deviation:

Answer:
AE = 15 cm; ED = 18 cm; AD = 15 cm (given)
Step-by-step explanation:
ΔBEC ~ ΔAED so ...
AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE
Substituting given numbers (lengths in centimeters), we have ...
15/10 = 1 + 5/BE
1/2 = 5/BE
BE = 10
Similarly, ...
1/2 = 6/CE
CE = 12
Then the unknown sides are ...
AE = AB + BE = 5 + 10 = 15 . . . cm
ED = CE + CD = 12 + 6 = 18 . . . cm
Volume of a cylinder= (height) x area of the base (circle)
We know the height = 160 cm (given), let's find the radius of the base.
The circumference of the base = 87.92 = 2πR==> R=87.92/(2π) =13.993 cm
Area of circle = πR²=π(13.993)² = 615.128 cm²
Hence the volume of the cylinder = 615.128 x 160 = 92,420.48 cm³
Oh round that up to three, since 6 is above 5. BRAINLIEST ANSWER PLEASEEEE