Question

The starch suspension contained 0.8 g of starch

Answer 1

Cell metabolic equilibrium actively maintained 33 degrees heat 1890 kv

Answer 2

Explanation:

We have given the 0.8 gm of starch contained in the starch suspension.

We need to find the mean rate of starch which digested at 33 degrees celcius.

We can apply the rate of digestion formula : $\frac{initial amount-0.8}{total time taken}$. It gives answer in gram per unit time.

To determine the rate of digestion we need the initial amount of starch which is not given in the question. That's why we can't solve this question without the initial amount of starch that was present and the time taken to reach the final amount of 0.8 gm.