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3 years ago

I'll give brainliest if you show your answer. Plz answer before thirty minutes.

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

<h2>Answer:</h2>

The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

<h2>Step-by-step explanation:</h2>

We are given the mean and mean absolute deviation of two teams in a table as:

Team A Team B

Mean 127.9 s 127.4 s

Mean Absolute Deviation 0.26 s 0.23 s

The difference of mean between two team is: 0.5 s

( Since 127.9-127.4=0.5 s)

Also, the difference of Mean absolute deviation is: 0.03 s

( Since, 0.26-0.23=0.03 s)

Now let the difference of the mean times be equal t n times the difference of the mean absolute deviation of two teams

i.e.

0.5=n×0.03

⇒ n=0.5/0.03

⇒ n=16.6667

which is approximately equal to 16.

<em>Hence, The difference between the mean times is about 16 times the mean absolute deviation of the data sets.</em>

Sholpan [36]3 years ago

3 0

The difference between the mean times is about 16 times the mean absolute deviation of the data set.

127.9-127.4=0.5
0.26-0.23=0.03
0.5/0.03=16.6666

About 16 times

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