Question

I'll give brainliest if you show your answer. Plz answer before thirty minutes.

Answer 1

Answer:

The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Step-by-step explanation:

We are given the mean and mean absolute deviation of two teams in a table as:

                                              Team A           Team B

             Mean                        127.9 s             127.4 s

Mean Absolute Deviation     0.26 s             0.23 s

The difference of mean between two team is: 0.5 s

( Since 127.9-127.4=0.5 s)

Also, the difference of Mean absolute deviation is: 0.03 s

( Since, 0.26-0.23=0.03 s)

Now let the difference of the mean times be equal t n times the difference  of the mean absolute deviation of two teams

i.e.

      0.5=n×0.03

⇒ n=0.5/0.03

⇒ n=16.6667

which is approximately equal to 16.

Hence, The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Answer 2

The difference between the mean times is about 16 times the mean absolute deviation of the data set.

127.9-127.4=0.5
0.26-0.23=0.03
0.5/0.03=16.6666

About 16 times