<h2>
Answer:</h2>
The difference between the mean times is about 16 times the mean absolute deviation of the data sets.
<h2>
Step-by-step explanation:</h2>
We are given the mean and mean absolute deviation of two teams in a table as:
Team A Team B
Mean 127.9 s 127.4 s
Mean Absolute Deviation 0.26 s 0.23 s
The difference of mean between two team is: 0.5 s
( Since 127.9-127.4=0.5 s)
Also, the difference of Mean absolute deviation is: 0.03 s
( Since, 0.26-0.23=0.03 s)
Now let the difference of the mean times be equal t n times the difference of the mean absolute deviation of two teams
i.e.
0.5=n×0.03
⇒ n=0.5/0.03
⇒ n=16.6667
which is approximately equal to 16.
<em>Hence, The difference between the mean times is about 16 times the mean absolute deviation of the data sets.</em>
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