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ddd [48]
3 years ago
8

joanne bought 3 baseball cards for $160. if the first card was as expensive as the combined price of the second and the third ca

rds, and the second card cost $20 more than the third card, what is the price of the first card?
Mathematics
1 answer:
BARSIC [14]3 years ago
4 0
Let the price of the 3rd card be c. Now we can write the equation:
c + (c + 20) + (c + c + 20) = 160 .........(1)
Simplifying the left hand side of equation (1), we get:
4c + 40 = 160 .........(2)
Subtracting 40 from both sides of equation (2) gives:
4c = 120
from which c = $30.
Therefore the price of the second card = 30 + 20 = $50
and the price of the first card = 30 + 50 = $80.
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