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ddd [48]
3 years ago
8

joanne bought 3 baseball cards for $160. if the first card was as expensive as the combined price of the second and the third ca

rds, and the second card cost $20 more than the third card, what is the price of the first card?
Mathematics
1 answer:
BARSIC [14]3 years ago
4 0
Let the price of the 3rd card be c. Now we can write the equation:
c + (c + 20) + (c + c + 20) = 160 .........(1)
Simplifying the left hand side of equation (1), we get:
4c + 40 = 160 .........(2)
Subtracting 40 from both sides of equation (2) gives:
4c = 120
from which c = $30.
Therefore the price of the second card = 30 + 20 = $50
and the price of the first card = 30 + 50 = $80.
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Step-by-step explanation:

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Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
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Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

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step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

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rusak2 [61]

Answer:

The answer is 1.21.

Step-by-step explanation:

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I hope this was clear!

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